Gate 2009 chemical engg answer keys
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Monday, February 9, 2009
ATTENTION CHEMICALENGG GATE KEY
Posted by tranquil at 9:40 PM
Labels: Education News
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1 comments:
Answer to ques 59 is c coz
By the performance eqn. of CSTR
t = (Cao-Ca)/-ra
and –ra = kCa^0.5
this employes that t = 5 = ( 8 - 4 )/[ k (4)^0.5 ]
this gives k = 0.4 ( gmaol/litre )^0.5 .min^-1
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